Question

Write the equation of a line that passes through the points (-1, 3)and (2,6)

Answer 1

The equation of a line in 2 point form is

`(y-y_1)/(x-x_1)=(y_2-y_1)/(x_2-x_1)`

So, inputting the points, we have

`\begin{gathered} (y-3)/(x+1)=(6-3)/(2+1) \\ (y-3)/(x+1)=(3)/(3)=1 \\ \text{cross multiply} \\ y-3=x+1 \\ y=x+4 \end{gathered}`

So, the equation of our line is y = x + 4