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y=5x^2 + 2find the minimum or maximum value of the function. describe the domain and range of the function, and where the function is increasing and decreasing.I'm not sure where to begin

1 Answer

1 vote

From the given equation,


y=5x^2+2

Now,

For find the maximum and minimum value of the function,

The maximum and minimum of the function is,


\begin{gathered} y=5x^2+2 \\ x=-(b)/(2a) \\ =-(0)/(2*5) \\ =0 \end{gathered}

Then,

Put the value of x into the given equation to find the value of y,

So;


\begin{gathered} y=5(0)^2+2 \\ y=0+2 \\ y=2 \end{gathered}

Hence, the maximum and minimum function is,

(0, 2).

Now,

The domain of the given funcytion is,


(-\infty,\text{ }\infty)

And,

The range of the given function is,


\begin{gathered} y=5x^2+2 \\ f(x)\ge2 \end{gathered}

So,

The range of function is,


\lbrack2,\text{ }\infty)

The increasing and decreasing of the function is,


\begin{gathered} \text{Increasing:- }(0,\text{ }\infty) \\ \text{Decreasing:- }(-\infty,\text{ 0)} \end{gathered}

answered
User Nedned
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