Question

I need some help pls been out of school 7 weeks for covid and so confused

Answer 1

Given:

`3x+y=4\ldots\ldots\ldots\ldots\text{ take it as equation (1).}`
`6x+2y=8\ldots\ldots\ldots\ldots\text{ take it as equation (2).}`

Multiply both sides of the equation (1) by 2, we get

`(2)3x+(2)y=(2)4`

`6x+2y=8\ldots\ldots\ldots\ldots\text{ take it as equation (3).}`

Subtract equation (2) from equation (3), we get

`(6x+2y)-(6x+2y)=8-8`
`0=0`

We obtain equation (2) by multiplying 2 and equation (1).

Equation 2 is dependent on equation (1).

We know that a dependent system has an infinite number of solutions.

The solution of the system has many solutions.