Question

Calculate the molarity of a solution containing 0.65 moles of NaCI in 3.50 L of solution

Answer 1

The molarity of the solution is 0.19M. (first option)

Step-by-step explanation:

The given information from the exercise is:

- Moles of NaCl (n): 0.65 moles

- Volume of solution (V): 3.50L

To calculate the molarity of the solution we have to replace the values of n and V in the Molarity formula:

`\begin{gathered} M=\frac{n\text{ \lparen moles of solute\rparen}}{V(volume\text{ of solution})} \\ M=(0.65moles)/(3.50L) \\ M=0.19M \end{gathered}`

So, the molarity of the solution is 0.19M.