Question

An angle measures 3° more than two times its complement x please explain

Answer 1

Given that;

An angle measures 3° more than two times its complement x.

Let the larger angle be y

`x+y=90\degree`

The angle measures 3° more than two times its complement, i.e.

`y=(2x+3)\degree`

Then,

`\begin{gathered} x+y=90\degree \\ x+(2x+3)\degree=90\degree \\ x\degree+2x\degree+3\degree=90\degree \\ 3x\degree=90\degree-3\degree \\ 3x=87\degree \\ x=(87\degree)/(3) \\ x=29\degree \end{gathered}`

The smaller angle, x is 29 degrees

The larger angle is

`y=2x+3=2(29)+3=58+3=61\degree`

The larger angle, y is 61 degrees

The total is

`x+y=29+61=90\degree`

The total is 90 degrees.