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1 Answer

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Solution

- To solve the question, we should bring the integrals with the same lower bound together.

- Thus, we have:


\begin{gathered} \int_(-2)^2f(x)+\int_2^5f(x)-\int_(-2)^(-1)f(x) \\ \\ \int_(-2)^2f(x)-\int_(-2)^(-1)f(x)+\int_2^5f(x) \\ \\ \int_(-1)^2f(x)+\int_2^5f(x) \\ \\ =\int_(-1)^5f(x) \end{gathered}

Final Answer

The answer


\begin{gathered} a=-1 \\ b=5 \end{gathered}

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User Tanvi B
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