Question

HELP DUE IN 10 MINS!!!!!!In AGHI, the measure of ZI=90°, the measure of ZG=31°, and IG = 60 feet. Find thelength of HI to the nearest tenth of a foot.

Answer 1

36.1 feet.

Step-by-step explanation:

From the diagram:

• The side length ,opposite ,angle 31° = x

,

• The side length ,adjacent to ,angle 31° = 60

Recall from trigonometry that:

`\tan \theta=\frac{\text{Opposite}}{\text{Adjacent}}`

This implies that:

`\tan 31=\frac{\text{x}}{\text{6}0}`

Cross multiply:

`\begin{gathered} x=60*\tan 31\degree \\ x=36.1\text{ feet} \end{gathered}`

The length of HI is 36.1 feet (to the nearest tenth of a foot).