answer and explanation
to correctly answer this question we first need to look at the mol ratio of the balanced stoichiometric equation
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
from this balanced equation we see that 2 mols of NaOH will be neutralized by 1 mol of sulfuric acid. therefore the mols ratio is
H₂SO₄: NaOH
1:2
if we have 0.70 mol of NaOH then we need :
(0.70 x1)/2 = 0.35 mols of sulfuric acid