Question

The width of a rectangle is 10 feet more than the length. The perimeter is 140 feet. Find the length and width.Width =Length=

Answer 1

Given;

`w=l+10,P=140ft`

The perimeter of a rectangle is;

`\begin{gathered} P=2(l+w) \\ \\ 140=2(l+l+10) \\ \\ (140)/(2)=2l+10 \\ \\ 70-10=2l \\ \\ 2l=60 \\ \\ l=(60)/(2) \\ \\ l=30ft \end{gathered}`

Then;

`\begin{gathered} w=30+10 \\ \\ w=40ft \end{gathered}`

CORRECT ANSWER:

`\begin{gathered} Width=40ft \\ \\ Length=30ft \end{gathered}`