Question

Find the degree measure of the angle or the intercepted arc indicated in each figure

Answer 1

Let's solve point a of the question. To calculate the diameter of the figure we can solve it using the Pythagorean theorem

`\begin{gathered} NK=√(NL^2+KL^2) \\ NK=√(12^2+5^2) \\ NK=√(144+25) \\ NK=√(169) \\ NK=13 \end{gathered}`

Let us now calculate part b.

`mNLK=180`

Let us now calculate part c.

`mNJK=180`

Now let us calculate the arc for the part d. As it is a right triangle it would be:

`m\angle NLK=90`

Now let us calculate for part e

`mKL=45.2`

Finally, for part f

`\begin{gathered} mNL=180-45.2 \\ mNL=134.8 \end{gathered}`