Question

Part A) log₂ (x) = 6x=Part B) 9² = 612x=Part C) In(x) = 3.5x =

Answer 1

Given:

`\log_2x=6`

Required:

To find the value of x.

Step-by-step explanation:

We know that

`\begin{gathered} \log_ax=b \\ \\ x=a^b \end{gathered}`

Consider

`\begin{gathered} \log_2x=6 \\ \\ x=2^6 \\ \\ x=64 \end{gathered}`

Final Answer:

`x=64`