Question

How do I get this one done? Can someone help me with d?

Answer 1

`(6x)/(x-3)/(2x)/(4x-12)`
`\begin{gathered} (6x)/(x-3)*(4x-12)/(2x) \\ (6x)/(x-3)*(4(x-3))/(2x) \\ (6x(4x-12))/(2x(x-3)) \\ (6(4x-12))/(x-3) \end{gathered}`

The Solution is:

`x<3\text{ or x>3}`

The interval notation:

`(-\infty,3)\text{ U (}3,\infty)`