Question

The length of a rectangle is 11 ft more than double the width, and the area of the rectangle is 63 ft^2. Find the dimensions of the rectangle.

Answer 1

STEP 1: Identify and Set up

We have two variables that their product give us the area. We are also subtly given dimensions of our rectangle. Our approach will be to set up equations using the variables provided and later solve simultaneously.

STEP 2: Execute

Let l represent length

Let w represent width

We also know that:

`\begin{gathered} l=11+2w,\text{ and} \\ lw=63 \end{gathered}`

We now have a pair of equations we can solve simultaneously.

We can substitute the value of l from the 1st equation into the 2nd to get: