Question

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Answer 1

We need to solve the following equation by completing the square:

`x^2-4x-9=0`

we first pass the 9 to sum in the right side

`x^2-4x=9`

now we add 4 in both sides of the equation, because (4/2)^2=4, obtaining

`x^2-4x+4=9+4`

simplifying

`(x-2)^2=13`

then

`(x-2)=\pm\sqrt[]{13}`

adding 2 in both sides of the equation we have that the solution is:

`x=2\pm\sqrt[]{13}`