Question

Show where the expression in number 8 would be on a unit circle

Answer 1

Step 1:

Write the expression

`cos270\text{ }`

Step 2

`\begin{gathered} cos270\text{ = 0} \\ sin270\text{ = -1} \\ (0,\text{ -1\rparen} \end{gathered}`

Question 8 Second part

`\begin{gathered} sin((16\pi)/(3))\text{ = sin960 = sin\lparen960 - 2}*360)\text{ = sin240} \\ sin((16\pi)/(3))\text{ = }(-√(3))/(2) \\ cos((16\pi)/(3))\text{ = }(-1)/(2) \end{gathered}`
`((-1)/(2),\text{ }(-√(3))/(2))`