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How do you find the value of x?DE = 5x and KC = 3x + 12

How do you find the value of x?DE = 5x and KC = 3x + 12-example-1

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\begin{gathered} DE=5x \\ KC=3x+12 \end{gathered}

If KC and DE are congruent lines (The figure is a parallelogram) You can equal the given equations:


\begin{gathered} DE=KC \\ \\ 5x=3x+12 \end{gathered}

Use the equation above to solve for x:


\begin{gathered} 5x-3x=12 \\ 2x=12 \\ x=(12)/(2) \\ \\ x=6 \end{gathered}Then, the value of x is 6
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