Question

Write an equation of the line that passes through point P and is perpendicular to the line with the given equation:P(2,0) y= -5

Answer 1

Y = mx + c

point p = (2 , 0)

x1 = 2 and y1 = 0

the line with y = -5

for y = -5 then x = 0

(0 , -5)

slope = y2 - y1 / x2 - x1

x1 = 2, y1 = 0, x2 = 0 and y2 = -5

slope = -5 - 0 / 2 -0

slope = -5/2

(y - y1) = m(x - x1)

y - 0 = -5/2(x - 2)

y = -5/2 *x - (-5/2 *2)

y = -5/2x + 5/2 *2

y = -5/2x + 1