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Set y=0 and apply the zero product property
y = x {}^(2) + 2x - 3

1 Answer

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Given:


y=x^2+2x-3
\begin{gathered} 0=x^2+2x-3 \\ 0=x^2-x+3x-3 \\ 0=x(x-1)+3(x-1) \\ 0=(x-1)(x+3) \end{gathered}
x=1,-3

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User VishB
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