Question

Q.2 Arithmetic sequencesCYCWhat is the next fraction in this sequence?

Answer 1

19/32

Explanation:

We have the following sequence:

`(7)/(32),\:(10)/(32),\:(13)/(32),\:(16)/(32),\:...`

We calculate the common difference:

`\begin{gathered} d=(16)/(32)-(13)/(32)=(3)/(32) \\ \\ d=(13)/(32)-(10)/(32)=(3)/(32) \\ \\ d=(10)/(32)-(7)/(32)=(3)/(32) \\ \\ \text{ Therefore, the following term would be:} \\ \\ t=(16)/(32)+(3)/(32)=(19)/(32) \end{gathered}`

The correct answer is 19/32