Question

-3x >=9 using the symbols ( [ { in set builder notation the solution set is

Answer 1

The given inequality :

`-3x\ge9`

Simplify :

Multiply both side by (-1) and reverse the inequality :

`\begin{gathered} -3x\ge9 \\ (-1)(-3x)\leq(-1)9 \\ 3x\leq(-9) \end{gathered}`

Divide the inequality by 3:

`\begin{gathered} (3x)/(3)\leq((-9))/(3) \\ x\leq(-3) \end{gathered}`

i.e. x is less than or equal to (-3)

Solution : x ≤ (-3)

so,

x is lies in the half open interval of - infinity to (-3)

Interval Notation : (-infinity, -3]

Answer:

Solution : x ≤ (-3)

Interval Notation : (-infinity, -3]