Question

Charles made a business trip of207 miles. He averaged60 mph for the first part of the trip and49 mph for the second part. If the trip took4 hours, how long did he travel at each rate?

Answer 1

Let:

t = travel time

60t + 49(4 - t) = 207

60t + 196 - 49t = 207

11t + 196 = 207

Solving for t:

11t = 207 - 196

11t = 11

t = 11/11

t = 1

4 - t = 3

Therefore he drive at 60mph for 1 hour and at 49mph for 3 hours