Question

2) After the elevator accelerates, then it moves at a constant speed of 6.0m/s, calculate the tensionthe cable.

Answer 1

Given,

The mass of the elevator, m=5000 kg

The velocity of the elevator, v=6.0 m/s

As the elevator is moving at a constant speed, the net force on the elevator is zero. That is the downward force, the weight of the elevator is balanced by the upward force, the tension in the cable.

Thus the tension in the cable is given by,

`T=mg`

Where g is the acceleration due to gravity.

On substituting the known values,

`\begin{gathered} T=5000*9.8 \\ =49000\text{ N} \end{gathered}`

Thus the tension in the cable is 49000 N