Question

Consider a triangle A BC lIke the one below. Suppose that B=31°, a =53, and c= 12. (The figure Is not drawn to scale.) Solve the triangle.Carry your intermediate computations to at least four decimal places, and round your answers to the nearest tenth.If there Is more than one solution, use the button labeled "or"

Answer 1

Given,

The measure of angle B is 31 degree.

The measure of side a is 53.

The measure of side c is 12.

By law of cosine,

`\begin{gathered} b^2=a^2+c^2-2accosB \\ b^2=2809+144-1272cos31^(\circ) \\ b^2=1862.68319 \\ b=43.1588 \\ b=43.16 \end{gathered}`

By law of sine,

`\frac{}{}A=140.77^{^(\circ)}`

The measure of angle C is 8.23 degree.