Question

Pls helpp ive tried solving many times and each time i get a different answer

Answer 1

y= 8
`√(3)` x=12

Explanation:

In this question we will be doing trigonometry (SOH=sine CAH= cosine TOA=tangent) (SIN=sine COS= cosine TAN=tangent)

Find value of y

1. First, we label the triangle the side opposite the 90degrees is called hypotenuse(h) the side opposite 60 degrees is called opposite (o) the remaining side is called the adjacent (a) (4
`√(3)` )

2. From this we can see to find the value of y we need the hypotenuse (h) which is labeled as y and the adjacent (a) which is labelled as 4
`√(3)`

3. Therefore we use cosine equation. We subsite the values in and rearrange to get y on it is own and then find the value of y.

cos(angle)=
`(adjacent)/(hypotenuse)`

cos(60)=
`(4√(3) )/(y)`

y=
`(4√(3) )/(cos(60))`

y= 8
`√(3)`

Find value of x

1. First, we label the triangle the side opposite the 90degrees is called hypotenuse(h) the side opposite 60 degrees is called opposite (o) the remaining side is called the adjacent (a) (4
`√(3)` )

2. From this we can see to find the value of x we need the opposite (o) which is labeled as x and the adjacent (a) which is labelled as 4
`√(3)`

3. Therefore we use the tangent equation. We substitute the values in and rearrange to get x on its own and then find the value of x

tan(angle)=
`(opposite)/(adjacent)`

tan (60)=
`(x)/(4√(3) )`

4
`√(3)` x tan(60)= x

x= 12