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Rewrite logsub11 38 as a base 10 then estimate the value to 3 decimal places.

asked
User Roshimon
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1 Answer

3 votes
Answer:

The estimated value is 1.518

Step-by-step explanation:

Given


\log_(11)38

This is written in base 10 as follows:


(log38)/(log11)=(1.580)/(1.041)=1.518

answered
User Vegeta
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