Question

Answer this question and break it down using the following(Huge equation, show work if needed) this process involves breaking down the expression and answering the given.

Answer 1

Given:

`y=x^2-3x-4`

1) Function notation

`f(x)=x^2-3x-4.`

2) put x=-2

`\begin{gathered} f(-2)=(-2)^3-3(-2)-4 \\ f(-2)=2^2+3\cdot\: 2-4 \\ f(-2)=4+6-4 \\ f(-2)=6 \end{gathered}`

3) Put x=-1

`\begin{gathered} f(-1)=(-1)^3-3(-1)-4 \\ f(-1)=1+3-4 \\ f(-1)=0 \end{gathered}`

4) f(x)=-4 to find x.

when x =0 f(x)=-4

when x=3 f(x)=-4