Question

Find the equation of the straight line that passes through the points -3, -5 and 2, -11. First, what is the slope? Next write the equation in point slope form not slope intercept form using -3 -5 as the point. Now right the equation in point slope form and not slope intercept form, using 2, -11 as the point simplifying double negatives. Then simplify either of the point slope equation‘s to write the equation in slope intercept form.

Answer 1

Given:

`(-3,-5)\text{ and (2,-11) are the given points.}`
`\begin{gathered} \text{Slope(m)}=(y_2-y_1)/(x_2-x_1) \\ \text{Slope(m)}=(-11+5)/(2+3) \\ \text{Slope(m)}=-(6)/(5) \end{gathered}`

Equation of straight line with the point(2,-11) and slope is

`\begin{gathered} y-y_1=m(x-x_1) \\ y+11=-(6)/(5)(x-2) \\ 5(y+11)=-6(x-2) \\ 5y+55=-6x+12 \\ 6x+5y+55-12=0 \\ 6x+5y+43=0 \end{gathered}`

Equation in slope intercept form

`y=-(6)/(5)x-(43)/(5)`