Question

Find the slopes of lines PQ and PR. (Assume a ≠ -b.) P(a, a + b); Q(a + b, b); R(a - b, a)slope of PQ = ?slope of PR = ?

Answer 1

We know that the slope of a line is:

`m=(y_2-y_1)/(x_2-x_1)`

So for the line PQ will be:

`m=(b-(a+b))/(a+b+a)=(-a)/(2a+b)`

and for the line PR will be:

`m=(a-(a+b))/(a-b-a)=(-b)/(-b)=1`