Question

Alice is deciding where to go on her next trip. She is reviewing some information packets. She has packets advertisingEuropean trips numbered 1, 2, 3, packets advertising African trips numbered 1, 2, 3, 4, 5, 6, and packets advertising SouthAmerican trips numbered 1, 2. If a single packet is picked at random, what is the probability that the packet is advertising a South American trip AND has an odd number

Answer 1

The probability that the packet is advertising a South American trip AND has an odd number is 1/11.

Step-by-step explanation:

The total number of packets is:

3 (European) + 6 (African) + 2 South American = 11

From the packets, there are 2 South Americans, but only one has an odd number.

Thus, the probability that the packet is advertising a South American trip AND has an odd number is:

1/11.