Question

If ABCD is dilated by a factor of 3, thecoordinate of B' would be:4С3B.2-5-2 -1 0-4نما12.4 53-1A-2D-3B' = ([?], [ ]

Answer 1

For this case the origianl coordinate for B is:

B= (-2,2)

After a dilation of factor 3 we got:

B' = (-6, 6)