Question

1404 0. An automobile's velocity, starting from a complete stop, is v(t) =5t - 6 where vis measured in feet per second. After what elapsed time would the automobile reach a velocity of 44 feet per second?

Answer 1

We have

`v(t)=5t-6`

where v is the velocity and t is the time

we have

v =44 ft per second

we need to substitute the values given in the equation given

`44=5t-6`

then we isolate t

`\begin{gathered} 5t=44+6 \\ 5t=50 \\ t=(50)/(5) \\ t=10\sec \end{gathered}`