Question

Find the equation of the line with slope = -2 and passing through (-8,-1). Write your equation inpoint-slope form y - y1 = m(2 – x1) AND slope-intercept forms.point-slope form:slope-intercept form:

Answer 1

The point-slope form of the line is:

`y-y_1=m\cdot(x-x_1)`

Where m is the slope and the line passes through the point (x1, y1)

Given: the slope = m = -2

And the line passes through the point (-8,-1)

Substitute with the slope and the point into the equation of the line:

`\begin{gathered} y-(-1)=-2(x-(-8)) \\ y+1=-2(x+8) \end{gathered}`

Solve the equation for y to get the slope-intercept form

`\begin{gathered} y+1=-2x-16 \\ y=-2x-17 \end{gathered}`

So, the answer will be:

point-slope form ⇒ y+1 = -2(x+8)

slope-intercept form ⇒ y = -2x - 17