Question

11,How many different committees can be formed from 10 teachers and 38 students if the committee consists of 4 teachers and 3 students?The committee of 7 members can be selected in different ways.Help me solve thisView an example Get more help -

Answer 1

Let C(n, r) denotes the combination of n object selecting r and it is defined as

`C(n,r)=(n!)/((n-r)!r!)`

The number of ways will be

`\begin{gathered} Number\text{ }Of\text{ }Ways=C(10,4)* C(38,3) \\ \\ Number\text{ }Of\text{ }Ways=(10*9*8*7*6!)/(6!4!)*(38*37*36*35!)/(35!3!) \\ \\ Number\text{ }Of\text{ }Ways=210*8436 \\ \\ Number\text{ }Of\text{ }Ways=1771560 \end{gathered}`