Question

Which is the solution set for the equation 2x^2-3x+1 =0

Answer 1

Given the equation

`2x^2-3x+1=0`

the solution can be found with the quadratic formula, as follows:

`\begin{gathered} x_(1,2)=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x_(1,2)=\frac{3\pm\sqrt[]{(-3)^2-4\cdot2\cdot1}}{2\cdot2} \\ x_(1,2)=\frac{3\pm\sqrt[]{9^{}-8}}{4} \\ x_(1,2)=(3\pm1)/(4) \\ x_1=(3+1)/(4)=1 \\ x_2=(3-1)/(4)=(1)/(2) \end{gathered}`

The solution set is {1/2, 1}