Question

Daniel: GeometryGiven a circle with a diameter of 22 millimeters, which expression can be used to find the area of the sector formed by acentral angle of 18 and what is the area?184. 4840360and 24.211 mar?18360and 605 11 mmOB, 121718180C.4847and 48A mmmm218D.12171- 10and 12,1 11 mm18

Answer 1

`\text{Area of a sector = }(\theta)/(360)*\pi* r^2`
`\begin{gathered} \theta=\text{ 18 degre}es \\ r\text{ = 11mm} \end{gathered}`
`\text{Area =121(}(18)/(360))\pi mm^2`

or

`6.05\pi mm^2`