Question

Please help me solve question 2 on my algebra 1 hw

Answer 1

We will solve this problem thus:

`\begin{gathered} 3y-2=(4)/(3)y+5 \\ \text{Collect like terms} \end{gathered}`
`\begin{gathered} 3y-(4)/(3)y=5+2 \\ (5)/(3)y=7 \\ 5y=21 \\ y=(21)/(5) \end{gathered}`

Now we will find the value of y-1 thus:

`\begin{gathered} y-1 \\ =(21)/(5)-1 \\ =(21)/(5)-(1)/(1) \\ =(21-5)/(5) \\ =(16)/(5) \end{gathered}`