Question

QuestionIn PQR, sin P = 1/3, sin R = 2/3,and p = 9. Find the side length r.

Answer 1

Lets draw our triangle:

Lets use the "Law of Sines" to find our side r:

`(p)/(\sin P)=(r)/(\sin R)\rightarrow(9)/((1)/(3))=(r)/((2)/(3))\rightarrow9*(3)/(1)*(2)/(3)=r\rightarrow r=18`

So r=18