Question

solve for coefficient a in vertex from for the parabola in daredevil Danny's practice jump using key aspects from step 1. As you solve for the coefficient explain each step of the process in detail

Answer 1

`y=a(x-h)^2+k`

As the vertex is (h,k)

And in the given graph you have the vertex in (24,50)

You have the next:

`y=a(x-24)^2+50`

You use this equation and the value of x and y in the graph (example: (44,0)) to find the coefficient a:

`0=a(44-24)^2+50`

Solve the operation to remove parenthesis:

`\begin{gathered} 0=a(20)^2+50 \\ \\ 0=400a+50 \end{gathered}`

Substract 50 in both sides of the equation:

`\begin{gathered} 0-50=400a+50-50 \\ \\ -50=400a \end{gathered}`

Divide both sides of the equation into 400:

`\begin{gathered} -(50)/(400)=(400)/(400)a \\ \\ -(50)/(400)=a \end{gathered}`

Simplifty:

`a=-(50\cdot1)/(50\cdot8)=-(1)/(8)`Then, the value of coefficient a is -1/8