Question

What is the value of the discriminant for this quadratic: (1/4)x²+4=y

Answer 1

-4

Explanation:

Given any quadratic function of the form:

`y=ax^2+bx+c`

Its discriminant is obtained by using the formula:

`D=b^2-4ac`

Comparing our given equation with the form of a quadratic above, we have:

`y=(1)/(4)x^2+4\text{ }where\begin{cases}a=(1)/(4) \\ b=0 \\ c=4\end{cases}`

Therefore, the discriminant will be:

`D=b^2-4ac=0^2-4((1)/(4))(4)=0-4=-4`

The value of the discriminant for the given quadratic is -4.