Question

In AQRS, the measure of ZS=90°, QR = 71 feet, and SQ = 50 feet. Find the measure of ZR to the nearest degree.

Answer 1

we get that:

`\sin x=(11)/(32)\rightarrow x=\arcsin (11)/(32)=20.10^(\circ)\approx20^(\circ)^{}`