Question

Factor the quadratic equation below. x2 – 3x – 10 = 0 (x - 5) (x + 2) = 0 0 (x-3) (x - 10) = 0 O O O O(x-7)(x-3) = 0 O(x + 7) (x + 3) = 0

Answer 1

`(x+a)(x+b)=x^2+(a+b)x+ba`

We need a b in such a way that a+b = - 3 and a*b = - 10

`a\text{ = -5 b = 2}\rightarrow(x-5)\cdot(x+2)=0`