Question

59.69 liters of gas at atmospheric pressure is compressed into a 0.294 L gascylinder. What is the pressure (mm Hg) of the compressed gas if its temperatureremains constant?

Answer 1

To answer this question, we have to use Boyle's Law:

`P1V1=P2V2`

Where P1 and P2 are the initial and final pressures and V1 and V2 are the initial and final volumes.

Solve the equation for P2 and replace for the given values of P1, V1 and V2:

`\begin{gathered} P2=(P1V1)/(V2) \\ P2=(760mmHg\cdot59.69L)/(0.294L) \\ P2=154,300.68mmHg=1.54*10^5mmHg \end{gathered}`

It means that the pressure of the compressed gas is 1.54e5.

The correct answer is 1.54e5.