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The intensity of radiation at a distance x meters from a source is modeled by the function given by R(x)=kx2, where kk is a positive constant. Which of the following gives the average intensity of radiation between 10 meters and 50 meters from the source?

1 Answer

10 votes

This would be the average value of R(x) between 10 m and 50 m :


\displaystyle \frac1{50\,\mathrm m - 10\,\mathrm m} \int_(10\,\rm m)^(50\,\rm m) kx^2 \, dx

answered
User Bryan Ray
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