Question

How many moles of mercury are produced by the decomposition of 6.3 moles of mercury oxide? (10pts)2HgO(s) ⇨ 2Hg(l) + O2(g)

Answer 1

6.3 moles of mercury are produced.

Step-by-step explanation

Given:

The moles of mercury oxide that decompose = 6.3 mol

Equation: 2HgO(s) ⇨ 2Hg(l) + O2(g)

What to find:

The moles of mercury produced by the decomposition of 6.3 moles of mercury oxide.

Solution:

According to the balanced equation for the reaction;

2 moles of HgO produced 2 moles of Hg

6.3 moles of HgO will produce x moles of Hg

`\begin{gathered} x=\frac{6.3\text{ }mol\text{ }HgO}{2\text{ }mol\text{ }HgO}*2\text{ }mol\text{ }Hg \\ \\ x=6.3\text{ }mol\text{ }Hg \end{gathered}`

Hence, 6.3 moles of mercury are produced by the decomposition of 6.3 moles of mercury oxide.