Question

G(t)=(t+1)^2-20.25what is the vertex of the parabola? (___,___)

Answer 1

`\begin{gathered} (t+1)^2-20.25=0 \\ (t+1)^2-20.25=0 \\ t^2+t+1-2.25=0 \\ t^2+t-19.25=0 \end{gathered}`

Solving for t,

`\frac{-1\pm\sqrt[]{1+4*19.25}}{2}=(-1\pm8.8)/(2)=3.5;-5.5`