Question

A right circular cylinder is shown in the figure below with dimensions given in feet. What is the surface area, in square feet, of this cylinder?

Answer 1

The surface area of a regular cylinder is given by the following formula.

`A_{\text{surface}}=2(r^2\pi)+(2r\pi)h`

Where r is the radius and h is the height of the cylinder. In our case,

`\begin{gathered} r=4 \\ h=3 \\ \Rightarrow A_{\text{surface}}=2(16\pi)+2(4\pi)\cdot3=32\pi+24\pi=56\pi \\ \Rightarrow A_{\text{surface}}=56\pi \end{gathered}`

The answer is 56pi ft^2