Question

Classify the following conic section from its standardequation: x2 - 4y2 - 6x + 16y – 21 = 0.Use the paperclip button below to attach files.

Answer 1

We will have the following:

For the equation:

`x^2-4y^2-6x+16y-21=0`

When we operate we obtain:

`\Rightarrow(x-3)^2-4(y-2)^2-14=0`

Which represents an hyperbola.

This can be seen in the following graph: