Question

Given a solenoid with 8 turns. A magnet is dropped through the middle of the solenoid, and this induces an average voltage of 4.00 volts in the solenoid over a time of 6.00 s. What was the average change in magnetic flux through one turn in the solenoid in SI units? a)1.50B)3.00c)0.750

Answer 1

Given:

The number of turns in the solenoid, N=8

The induced voltage, V=4.00 V

The time interval, Δt=6.00 s

To find:

The average change in the magnetic flux.

Step-by-step explanation:

The emf induced due to the changing magnetic flux is given by the equation,

`V=N(\Delta\phi)/(\Delta t)`

Where Δφ is the change in the magnetic flux.

On rearranging the above equation,

`\Delta\phi=(V*\Delta t)/(N)`

On substituting the known values in the above equation,

`\begin{gathered} \Delta\phi=(4.00*6.00)/(8) \\ =3.00\text{ Wb} \end{gathered}`

Final answer:

Thus the average change in the magnetic flux through one turn in the solenoid is 3.00 Wb. Thus the correct answer is option B.