Question

Find mZABD and mZCBD given mZABC =111°A(-10x + 58)(6x + 41)BmZABD =and mZCBD =

Answer 1

Given;

`\begin{gathered} m\angle ABD=(-10x+58)^0 \\ m\angle CBD=(6x+41)^0 \\ m\angle ABC=111^0 \end{gathered}`

From the given diagram;

`m\angle ABD+m\angle CBD=m\angle ABC`

substituting the given;