Question

Calculate the pH of a 3.0 X 10-4 M HCl (aq) solution?Group of answer choices+ 4.00+10.48-10.48-3,52+3.52

Answer 1

Step 1

The reaction:

HCl (aq) => H+ + Cl-

[HCl] = [H+ ] = [Cl-] = 3.0x10^-4 M

This is a strong acid

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Step 2

pH is calculated as:

`pH\text{ = -log \lbrack H+\rbrack}`

Therefore, pH = - log (3.0x10^-4 M) = + 3.52

Answer: pH = +3.52